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Find My Content
Feb 08 2013 08:41 AM
Male
Comments
Dulin
29 Jun 2011 - 18:24Purin
25 Jun 2011 - 13:03Purin
25 Jun 2011 - 05:22Borg Lord
24 Jun 2011 - 17:47Migrant
24 Jun 2011 - 03:19Migrant
24 Jun 2011 - 00:56Migrant
22 Jun 2011 - 20:55Migrant
22 Jun 2011 - 03:50Migrant
22 Jun 2011 - 02:09Migrant
22 Jun 2011 - 02:02I just separated the square root of two from that part of the equation. Therefore the complete expression is:
Two hundred and forty two which multiplies the square root of two and is divided by two is equivalent to one hundred and twenty one and a half which multiplies ...
Migrant
21 Jun 2011 - 22:52Migrant
21 Jun 2011 - 20:47When simplifying expressions it is untidy to leave a square root in the denominator. what you do in that case is to multiply top and bottom by the same square root. In this case Sqr(2)/Sqr(2).
(243/Sqr(2))*(Sqr(2)/Sqr(2)) =
(243*Sqr(2))/2 =
121.5*Sqr(2)
Migrant
21 Jun 2011 - 07:35In case you're being silly and using a calculator, those also round irregular numbers after a certain number of significant figures.
If you want an unrounded solution you cannot simplify further than 121.5*Sqr(2).
;)
Migrant
21 Jun 2011 - 07:33(3^6)/(3*Sqr(2)) = (3^5)/Sqr(2) = (243*sqr(2))/2
This equals 121.5 multiplied by an irregular number. So he answer, too must be irregular. Now the only way to write it as a single number would be to approximate the value of sqr(2). (continued)
Mikaro
08 Apr 2011 - 03:35