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The first is X = 7/3
The second is Y = 13/3 assuming X = 7/3
The only problem is that 7/3 + 13/3 does not equal 1. There must be something missing from the equations.
Comments
Comment ID #6385
Complete with math! (For the record, I finished the seatwork
)
SkylineFaux .
Comment ID #6389
it looks like it stands tiss and that is norwegian for pee
Gullbrand .
Comment ID #6391
The first is X = 7/3
The second is Y = 13/3 assuming X = 7/3
The only problem is that 7/3 + 13/3 does not equal 1. There must be something missing from the equations.
Anonymous # .
Comment ID #6397
Or, what you said was a 2 is actually a z.
Under such circumstances, x=6/5, y=-1/5, z=-7/5
rocketpony .
Comment ID #6400
the third says x+y(_z_)=1
the space, ( I'm assuming should have been z) would be somewhere between 1/6 and 1/7
just did it in my head, an got too lazy to finish it...
David .
Comment ID #6413
That math ;___;
I forgot how simple math could beeee waahhh
Anonymous #1 .
Comment ID #6421
Awesome jacket it awesome

I'm cracking up at you guys figuring out the math
Sonata .
Comment ID #6422
you zetta sons of digits
(if anyone gets that reference I'll love you forever)
Sonata .
Comment ID #6499
@Gullbrand

Really? Goddamn it.
@people trying to solve the equation
rocketpony got it right.
@Sonata
Thanks.
SkylineFaux .